Compare Version Numbers – Python

Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:
0.1 < 1.1 < 1.2 < 13.37

Idea: make two versions same length. Not literally, but in runtime

class Solution:
    # @param {string} version1
    # @param {string} version2
    # @return {integer}
    
    ## Idea: make two versions same length. Not literally, but in runtime
    def compareVersion(self, version1, version2):
        v1 = version1.split(".")
        v2 = version2.split(".")
        len1 = len(v1);
        len2 = len(v2);
        
        for i in range(0, max(len(v1), len(v2))):
            if i >= len1:
                if int(v2[i]) > 0:
                    return -1
                continue
            if i >= len2:
                if int(v1[i]) > 0:
                    return 1
                continue
            if int(v1[i]) > int(v2[i]):
                return 1
            if int(v1[i]) < int(v2[i]):
                return -1
        return 0